does throw~ really sum signals? it says its a "summing bus" in the helpfile. If I throw several dense signals to a signal catch~ it would seem like it would just overload but it doesn't seem to. Can anyone shed light on how this object works?

in particular is there any need to do something like this:
[throw1~] [throw2~]
\ /
[+~]

[/~ 2]
before the output? or would throw~ combine them just fine as is?

b

Hi,

I think [catch~] adds signals together from all [throws~] with the same label, similarly to let's say how [dac~] works. So I suppose you'd need to make sure that the output signal is within a healthy range, else you will need some compressor or some sort of division like you say.

Cheers,
Gilberto

@Coalman as Gilberto says....... you still need to be careful with your levels......
David.

Take a look at this:

All [Scope~] objetcs are ranging from -2 to 2 in the example above. Each individual oscillator outputs signals between -1 and 1, and after the [catch~] the output is between -2 and 2.

ah ok...clear...great demo @gsagostinho, thanks a lot. I think what I will do is manage all the volumes before the throw~ objects rather than do some signal maths afterwards.

Correct me if I'm wrong, but doesn't any line-level object sum its signal inputs?

that is what I thought, but then I saw some patches where people had used [+~] prior to [throw~] so I wasn't sure how it was working. After all, couldn't you just as easily throw~ both signals and then have [catch~] sum them? that was the nature of my original question.
of course [/~] or [-~] don't sum their signal inputs sorry, I couldnt resist that

I think often people use [+~] before another signal object just for the sake of clarity. As @LiamG wrote, that's often not necessary, but sometimes it makes the patch clearer I believe.