How to patch y[n] = x[n]/samplerate + y[n-1] with x the input and y the output in Pure Data?

Now we are getting somewhere:

Is such a feedback loop as below forbidden in Pure Data? Can't get it to work...

Yes, it's forbidden. You can't loop signal objects like that. You have to use a [send~] / [receive~] pair to make the loop.

Thanks! Yes the loop is working now.

Is there a simple way to give a single pulse to startup the patch instead of the workaround in the red circle?

@Nobody said:

Is there a simple way to give a single pulse to startup the patch instead of the workaround in the red circle?

The best way I know is to create a two element array -- first value 1, second value 0 -- then tabplay~ to get the impulse.

[array define dirac]

[loadbang]
|
[t b b]
|     |
|     [; dirac resize 2; dirac 0 1 0(  <<-- message, not object
|
[tabplay~ dirac]

(From memory, maybe I got the array messages wrong)

hjh

Why isn't the patch below inverting the input signal?

@Nobody said:

Why isn't the patch below inverting the input signal?

If the -1 message isn't being transmitted, then *~ might not be multiplying by -1...?

Otherwise... what is it doing instead of inverting?

hjh

Thanks. I now have the following and it is working now.

Just put -1 as an argument, like this [*~ -1]

Ah - that's even better.