Hi all,

i'm having this problem, when i call an abstraction with $0-xxxxx i get this error when creating tables:

"error: 0-arr: no such object" (arr is for array, i'm naming the array "$0-arr")

with pairs of $0-sends and $0-recieves in the same patch there are no problems, but with tables i'm getting that, anyone knows what am i doing wrong?

best.

how are you creating tables? it looks like you might be doing it dynamically with message boxes?

have a look at this: http://puredata.hurleur.com/sujet-6417-dollar-signs-objects-messages

thanks,

so, i can't use $0-xxx in a message?
i just want to resize a table dynamically and read it form an expresion object.
with the expr object i get a different error -> "error: no such table 'arr' "

i've attached a very simplified version, but if that works i can deal with everything else. any ideas?

thanks again.

http://www.pdpatchrepo.info/hurleur/test_0-array.pd

you CAN pass $0 into a message. my tutorial explains that too.

but in this case, you're probably better off just using a send object,

[resize $1 (
|

$ have a different function again, when used inside expr. I'm not sure how you'd get around that, but i have a feeling you won't be able to use the expr object with $0 array names.

http://www.pdpatchrepo.info/hurleur/test_0-array.pd

Two things:

1:

To change the size of an array with $0 using messages, I prefer to do this:

[hslider] <-- or whatever
|
[resize $1(
|

When you do something like [; array1 resize $1(, the first thing after a semi-colon is considered a [send] name, and what follows it is the message to that [send]. So you can always just use a [send] instead, and you won't have $0 issues. However, there are times when you want to use $0 in a message. In that case, do it like this:

[hslider]
|
[pack f $0]
|
[; $2-array resize $1(

$2 just takes on $0 in that case.

2:

To use $0-arraynames in [expr], you have to do something similar to message boxes using [expr]s variable system. Remember, $0 itself is a variable that holds a unique number, and [expr] interprets "-" as a minus sign. So, say $0 gets assigned as 1002. The way you have it now, [expr] is interpreting it as "1002 minus arr

• ", and there is no table named "arr". What you want to do is take advantage of the $s# variable in [expr]. This allows you to add symbols into [expr] (the name of an array is a symbol).

. [loadbang]
. / | \
. / | \
. [1( [1( [f $0]
. / | \
[0\ [0\ [0\ [symbol $1-arr(
| / | \
[expr $s4[$f1+$f2]*$f3]

You two have just created a monster

thanks, very much. Right away i'm going to work and fix everything.

best!

nice, didn't realize that symbols could be fed into expr.

Oh, yeah. It's a great vanilla-friendly way to grab the size of a table.

[symbol array1(
|
[expr size['$s1']]

And when the BSD version of [expr] finally comes around, it will be vanilla-friendlier.