Hi,

I'm stuck on what must be a simple problem, but I can't seem to figure it out.

I have a number - a GPS coordinate - that I am trying to split into Hours/Minutes/Seconds.

Lets say the number is 45.4388.
I can get the '45' and the 0.4388 easy enough by using a [trigger] , [int] , and [-] object. Eg.

[45.4388\
|
[t f f]
| |
[-] _
| |
[45\ [0.4388\

Now what I'm trying to do is parse the Minutes (43) and the Seconds (88), but I'm stuck on how to do that.

I've messed around with a list, trying to unpack it, a route object, etc with no luck.
One caveat that I should mention is that these numbers change frequently, so I can't do any pattern matching with stored values, like the route object would do, etc.

Also, it would be preferable for this to run in Pd Vanilla (though I can deal with it if not).

Thanks in advance...

~ Jesse_

maybe you could multiply the second number by 100 and then perform the first operation a second time?

just a guess.

0.4388* 100= 43.88
sorry, i'm not used to ascii art yet.

hey sensn... thansk for the reply.

nice trick, never thought of that! totally works.
still interested in any other solution, as I feel that there are objects for this that I am missing...

~ J

there is indeed a better object - [mod]

[mod] outputs 'modulus' of the input, so that any input is wrapped within the bounds specified by [mod]'s creation argument.

in this case, you want base 10, double digit numbers, so [mod 100] does the trick.

all that remains then, is to scale your original number so that the decimal sections become whole numbers.

so, for the 0.43 part, you multiply by 100 to get 43, and for the 0.0088 part, you multiply by 10000 to get 88

sweet eh?

all hail the great [mod]

( btw, [% ] works the same way, and as far as i can tell is exactly the same object )

http://www.pdpatchrepo.info/hurleur/mod%.pd

(except for negative # handling)

ahh, yes. Thanks seb. That's the difference.

Awesome, thanks. That makes total sense that it would be a modulus object, now that I think about it!