Is it possible to operate on all the instances of a [clone] object by multipling all of them (making a big AM/ring modulation of all the signals)?

Thanks!

Edit: aw crap, doesn't work for negative numbers. Can it be salvaged with an extra quadrant signal?

Edit: aw crap, doesn't work for negative numbers. Can it be salvaged with an extra quadrant signal?

You could take the log of the absolute values of each signal instead and fix the sign at the end: output 1 for each [clone] instance if the signal is negative (otherwise 0) and take the sum, mutiply the output of [exp~] by 1 if that sum is pair and by -1 if it's impair. More complaints from the efficiency police expected ... But I love the idea!

@inum Here is an example multiplyFactors.zip Please post sound output when you get it running to your satisfaction--I'm curious what you're trying to do.

in this case, the signal is passed through starting from the last instance. since the last instance doesn't have a corresponding sender, the [s~ 3-instance] becomes necessary with a constant signal of 1 as a factor. it would work as well in the opposite direction, of course. the cloned instances are all muted except for instance 0, which is the result of all multiplications.

this is a quick hack - not sure if it does what it's supposed to do. if you want to check, here are the 2 patches: test-am-clone.zip

without checking, i assume that it's exactly as you say since the instances are created in ascending order and i certainly introduced 1-block-delays that way as described in the help of s~/r~:

You have to get the [send~] sorted before the [receive~] or else you'll potentially get a one block delay.

(i'm actually not sure why it would only "potentially" happen)

... attaching an updated patch that's actually quite fun to play around with (in this case, the clone needs a second argument for the audible instance): test-am-clone.zip

EDIT: checked and confirmed now (that the sender should be in the previous instance).

[...] In my (much less nice) version [...] I just used the final [s~] to get the resulting signal.

after reading this, i mainly get the impression that your version might have been much less complicated!

... it seems so obvious now to just continue the chain from the last s~ instead of "sending" to nirvana and adding a logic to achieve the correct outlet~ result. damn. thanks!

This Log Exp trick is really amazing!!!