I simply want to send n bangs with x ms in between.

I can't wrap my head around why I can't feed the right inlet of a [delay] with x, send it's outlet to [f] with your typical [+ 1] loop, and loop the thing around back to the inlet, catching it once it reaches n with [sel n].

My faulty reasoning goes that a delayed bang output can bang the delay input (itself). But drawing that connecting will either hang Pd, or show an uncontrolled fast increase of [f] unrelated to delay time.

What am I not understanding?

Thanks!
Steve

edit: like this? bangs-with-delay.pd